Integrand size = 28, antiderivative size = 161 \[ \int \frac {\sec ^3(c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=-\frac {\left (a^2+b^2\right )^2}{2 a^2 b^3 d (b+a \cot (c+d x))^2}-\frac {\left (3 a^2-b^2\right ) \left (a^2+b^2\right )}{a^2 b^4 d (b+a \cot (c+d x))}+\frac {2 \left (3 a^2+b^2\right ) \log (b+a \cot (c+d x))}{b^5 d}+\frac {2 \left (3 a^2+b^2\right ) \log (\tan (c+d x))}{b^5 d}-\frac {3 a \tan (c+d x)}{b^4 d}+\frac {\tan ^2(c+d x)}{2 b^3 d} \]
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Time = 0.19 (sec) , antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {3167, 908} \[ \int \frac {\sec ^3(c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\frac {2 \left (3 a^2+b^2\right ) \log (\tan (c+d x))}{b^5 d}+\frac {2 \left (3 a^2+b^2\right ) \log (a \cot (c+d x)+b)}{b^5 d}-\frac {\left (3 a^2-b^2\right ) \left (a^2+b^2\right )}{a^2 b^4 d (a \cot (c+d x)+b)}-\frac {\left (a^2+b^2\right )^2}{2 a^2 b^3 d (a \cot (c+d x)+b)^2}-\frac {3 a \tan (c+d x)}{b^4 d}+\frac {\tan ^2(c+d x)}{2 b^3 d} \]
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Rule 908
Rule 3167
Rubi steps \begin{align*} \text {integral}& = -\frac {\text {Subst}\left (\int \frac {\left (1+x^2\right )^2}{x^3 (b+a x)^3} \, dx,x,\cot (c+d x)\right )}{d} \\ & = -\frac {\text {Subst}\left (\int \left (\frac {1}{b^3 x^3}-\frac {3 a}{b^4 x^2}+\frac {2 \left (3 a^2+b^2\right )}{b^5 x}-\frac {\left (a^2+b^2\right )^2}{a b^3 (b+a x)^3}+\frac {-3 a^4-2 a^2 b^2+b^4}{a b^4 (b+a x)^2}-\frac {2 a \left (3 a^2+b^2\right )}{b^5 (b+a x)}\right ) \, dx,x,\cot (c+d x)\right )}{d} \\ & = -\frac {\left (a^2+b^2\right )^2}{2 a^2 b^3 d (b+a \cot (c+d x))^2}-\frac {\left (3 a^2-b^2\right ) \left (a^2+b^2\right )}{a^2 b^4 d (b+a \cot (c+d x))}+\frac {2 \left (3 a^2+b^2\right ) \log (b+a \cot (c+d x))}{b^5 d}+\frac {2 \left (3 a^2+b^2\right ) \log (\tan (c+d x))}{b^5 d}-\frac {3 a \tan (c+d x)}{b^4 d}+\frac {\tan ^2(c+d x)}{2 b^3 d} \\ \end{align*}
Time = 3.65 (sec) , antiderivative size = 140, normalized size of antiderivative = 0.87 \[ \int \frac {\sec ^3(c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\frac {\frac {b^4 \sec ^4(c+d x)}{2 (a+b \tan (c+d x))^2}-2 a \left (-2 a \log (a+b \tan (c+d x))+b \tan (c+d x)-\frac {a^2+b^2}{a+b \tan (c+d x)}\right )+2 \left (a^2+b^2\right ) \left (\log (a+b \tan (c+d x))+\frac {3 a^2-b^2+4 a b \tan (c+d x)}{2 (a+b \tan (c+d x))^2}\right )}{b^5 d} \]
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Time = 2.27 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.71
method | result | size |
derivativedivides | \(\frac {-\frac {-\frac {b \tan \left (d x +c \right )^{2}}{2}+3 a \tan \left (d x +c \right )}{b^{4}}+\frac {\left (6 a^{2}+2 b^{2}\right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{5}}-\frac {a^{4}+2 a^{2} b^{2}+b^{4}}{2 b^{5} \left (a +b \tan \left (d x +c \right )\right )^{2}}+\frac {4 a \left (a^{2}+b^{2}\right )}{b^{5} \left (a +b \tan \left (d x +c \right )\right )}}{d}\) | \(115\) |
default | \(\frac {-\frac {-\frac {b \tan \left (d x +c \right )^{2}}{2}+3 a \tan \left (d x +c \right )}{b^{4}}+\frac {\left (6 a^{2}+2 b^{2}\right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{5}}-\frac {a^{4}+2 a^{2} b^{2}+b^{4}}{2 b^{5} \left (a +b \tan \left (d x +c \right )\right )^{2}}+\frac {4 a \left (a^{2}+b^{2}\right )}{b^{5} \left (a +b \tan \left (d x +c \right )\right )}}{d}\) | \(115\) |
risch | \(\frac {-12 i a \,b^{2}-24 a^{2} b +12 i a^{3}+12 a^{2} b \,{\mathrm e}^{6 i \left (d x +c \right )}+12 i a^{3} {\mathrm e}^{6 i \left (d x +c \right )}+36 i a^{3} {\mathrm e}^{4 i \left (d x +c \right )}+4 b^{3} {\mathrm e}^{2 i \left (d x +c \right )}+4 b^{3} {\mathrm e}^{6 i \left (d x +c \right )}+12 i a \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-4 i a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+4 i a \,b^{2} {\mathrm e}^{6 i \left (d x +c \right )}-36 a^{2} b \,{\mathrm e}^{2 i \left (d x +c \right )}+36 i a^{3} {\mathrm e}^{2 i \left (d x +c \right )}}{\left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{2} \left (b \,{\mathrm e}^{2 i \left (d x +c \right )}+i a \,{\mathrm e}^{2 i \left (d x +c \right )}-b +i a \right )^{2} b^{4} d}+\frac {6 \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right ) a^{2}}{b^{5} d}+\frac {2 \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right )}{b^{3} d}-\frac {6 \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) a^{2}}{b^{5} d}-\frac {2 \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{b^{3} d}\) | \(346\) |
norman | \(\frac {-\frac {2 \left (18 a^{4}+6 a^{2} b^{2}-b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{a^{2} d \,b^{3}}-\frac {2 \left (18 a^{4}+6 a^{2} b^{2}-b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{a^{2} d \,b^{3}}+\frac {2 \left (18 a^{4}-2 a^{2} b^{2}-3 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{a d \,b^{4}}-\frac {2 \left (18 a^{4}-2 a^{2} b^{2}-3 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{a d \,b^{4}}+\frac {2 \left (36 a^{4}+16 a^{2} b^{2}-2 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{b^{3} d \,a^{2}}-\frac {2 \left (6 a^{4}+2 a^{2} b^{2}-b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{b^{4} d a}+\frac {2 \left (6 a^{4}+2 a^{2} b^{2}-b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{b^{4} d a}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{2} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a \right )^{2}}-\frac {2 \left (3 a^{2}+b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{b^{5} d}-\frac {2 \left (3 a^{2}+b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{b^{5} d}+\frac {2 \left (3 a^{2}+b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a \right )}{b^{5} d}\) | \(440\) |
parallelrisch | \(\frac {48 \left (a^{2}+\frac {b^{2}}{3}\right ) \left (\frac {\left (a^{2}-b^{2}\right ) \cos \left (4 d x +4 c \right )}{4}+a^{2} \cos \left (2 d x +2 c \right )+a b \sin \left (2 d x +2 c \right )+\frac {a b \sin \left (4 d x +4 c \right )}{2}+\frac {3 a^{2}}{4}+\frac {b^{2}}{4}\right ) a^{2} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a \right )-48 \left (a^{2}+\frac {b^{2}}{3}\right ) \left (\frac {\left (a^{2}-b^{2}\right ) \cos \left (4 d x +4 c \right )}{4}+a^{2} \cos \left (2 d x +2 c \right )+a b \sin \left (2 d x +2 c \right )+\frac {a b \sin \left (4 d x +4 c \right )}{2}+\frac {3 a^{2}}{4}+\frac {b^{2}}{4}\right ) a^{2} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )-48 \left (a^{2}+\frac {b^{2}}{3}\right ) \left (\frac {\left (a^{2}-b^{2}\right ) \cos \left (4 d x +4 c \right )}{4}+a^{2} \cos \left (2 d x +2 c \right )+a b \sin \left (2 d x +2 c \right )+\frac {a b \sin \left (4 d x +4 c \right )}{2}+\frac {3 a^{2}}{4}+\frac {b^{2}}{4}\right ) a^{2} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (18 a^{4} b^{2}+7 a^{2} b^{4}-b^{6}\right ) \cos \left (4 d x +4 c \right )+4 \left (-6 a^{5} b -4 a^{3} b^{3}+a \,b^{5}\right ) \sin \left (2 d x +2 c \right )+2 \left (-6 a^{5} b +a \,b^{5}\right ) \sin \left (4 d x +4 c \right )-4 a^{2} b^{4} \cos \left (2 d x +2 c \right )-18 a^{4} b^{2}-3 a^{2} b^{4}+b^{6}}{2 a^{2} d \,b^{5} \left (2 a b \sin \left (4 d x +4 c \right )+a^{2} \cos \left (4 d x +4 c \right )-b^{2} \cos \left (4 d x +4 c \right )+4 a b \sin \left (2 d x +2 c \right )+4 a^{2} \cos \left (2 d x +2 c \right )+3 a^{2}+b^{2}\right )}\) | \(516\) |
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Leaf count of result is larger than twice the leaf count of optimal. 354 vs. \(2 (157) = 314\).
Time = 0.29 (sec) , antiderivative size = 354, normalized size of antiderivative = 2.20 \[ \int \frac {\sec ^3(c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\frac {24 \, a^{2} b^{2} \cos \left (d x + c\right )^{4} + b^{4} - 2 \, {\left (9 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )^{2} + 2 \, {\left ({\left (3 \, a^{4} - 2 \, a^{2} b^{2} - b^{4}\right )} \cos \left (d x + c\right )^{4} + 2 \, {\left (3 \, a^{3} b + a b^{3}\right )} \cos \left (d x + c\right )^{3} \sin \left (d x + c\right ) + {\left (3 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (2 \, a b \cos \left (d x + c\right ) \sin \left (d x + c\right ) + {\left (a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} + b^{2}\right ) - 2 \, {\left ({\left (3 \, a^{4} - 2 \, a^{2} b^{2} - b^{4}\right )} \cos \left (d x + c\right )^{4} + 2 \, {\left (3 \, a^{3} b + a b^{3}\right )} \cos \left (d x + c\right )^{3} \sin \left (d x + c\right ) + {\left (3 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (\cos \left (d x + c\right )^{2}\right ) - 4 \, {\left (a b^{3} \cos \left (d x + c\right ) + 3 \, {\left (a^{3} b - a b^{3}\right )} \cos \left (d x + c\right )^{3}\right )} \sin \left (d x + c\right )}{2 \, {\left (2 \, a b^{6} d \cos \left (d x + c\right )^{3} \sin \left (d x + c\right ) + b^{7} d \cos \left (d x + c\right )^{2} + {\left (a^{2} b^{5} - b^{7}\right )} d \cos \left (d x + c\right )^{4}\right )}} \]
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\[ \int \frac {\sec ^3(c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\int \frac {\sec ^{3}{\left (c + d x \right )}}{\left (a \cos {\left (c + d x \right )} + b \sin {\left (c + d x \right )}\right )^{3}}\, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. 652 vs. \(2 (157) = 314\).
Time = 0.28 (sec) , antiderivative size = 652, normalized size of antiderivative = 4.05 \[ \int \frac {\sec ^3(c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=-\frac {2 \, {\left (\frac {\frac {{\left (6 \, a^{5} + 2 \, a^{3} b^{2} - a b^{4}\right )} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {{\left (18 \, a^{4} b + 6 \, a^{2} b^{3} - b^{5}\right )} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} - \frac {{\left (18 \, a^{5} - 2 \, a^{3} b^{2} - 3 \, a b^{4}\right )} \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} - \frac {2 \, {\left (18 \, a^{4} b + 8 \, a^{2} b^{3} - b^{5}\right )} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {{\left (18 \, a^{5} - 2 \, a^{3} b^{2} - 3 \, a b^{4}\right )} \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac {{\left (18 \, a^{4} b + 6 \, a^{2} b^{3} - b^{5}\right )} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} - \frac {{\left (6 \, a^{5} + 2 \, a^{3} b^{2} - a b^{4}\right )} \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}}}{a^{4} b^{4} + \frac {4 \, a^{3} b^{5} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {12 \, a^{3} b^{5} \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {12 \, a^{3} b^{5} \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - \frac {4 \, a^{3} b^{5} \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} + \frac {a^{4} b^{4} \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}} - \frac {4 \, {\left (a^{4} b^{4} - a^{2} b^{6}\right )} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {2 \, {\left (3 \, a^{4} b^{4} - 4 \, a^{2} b^{6}\right )} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac {4 \, {\left (a^{4} b^{4} - a^{2} b^{6}\right )} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}}} - \frac {{\left (3 \, a^{2} + b^{2}\right )} \log \left (-a - \frac {2 \, b \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {a \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )}{b^{5}} + \frac {{\left (3 \, a^{2} + b^{2}\right )} \log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{b^{5}} + \frac {{\left (3 \, a^{2} + b^{2}\right )} \log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{b^{5}}\right )}}{d} \]
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Time = 0.39 (sec) , antiderivative size = 140, normalized size of antiderivative = 0.87 \[ \int \frac {\sec ^3(c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\frac {\frac {4 \, {\left (3 \, a^{2} + b^{2}\right )} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{b^{5}} + \frac {b^{3} \tan \left (d x + c\right )^{2} - 6 \, a b^{2} \tan \left (d x + c\right )}{b^{6}} - \frac {18 \, a^{2} b^{2} \tan \left (d x + c\right )^{2} + 6 \, b^{4} \tan \left (d x + c\right )^{2} + 28 \, a^{3} b \tan \left (d x + c\right ) + 4 \, a b^{3} \tan \left (d x + c\right ) + 11 \, a^{4} + b^{4}}{{\left (b \tan \left (d x + c\right ) + a\right )}^{2} b^{5}}}{2 \, d} \]
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Time = 27.02 (sec) , antiderivative size = 1204, normalized size of antiderivative = 7.48 \[ \int \frac {\sec ^3(c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\text {Too large to display} \]
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